Hi

Re TY, might recommend doing it the old fashion way

3x-4 √(3x^3 - 7x^2 + 7x -4)

You will find: (x^2 - x + 1)/(3x-4) = (x^2 - x + 1) 

using Synthetic  Division Technique and using 4/3 for the Divisor much like one would do if it were a root

2x-3 = 0, x = 4/3

that is as if (3x-4)3(x^3 - 7/3x^2 + 7/3x - 4/3) = 0  

0r (3x-4)( x^3 - 7/3x^2 + 7/3x - 4/3) = 0

4/3	1	-7/3	7/3	-4/3

		4/3	-4/3	4/3

	1	-1	1	0

(x^2 - x + 1)/(3x-4) = (x^2 - x + 1)  

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