SOLUTION: 3(2y-1)=7-2(y-3)

Question 91112: 3(2y-1)=7-2(y-3)
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
3(2y-1)= 7 - 2(y-3)
:
Multiply what's inside the brackets and you have:
6y - 3 = 7 - 2y + 6: "neg outside the brackets, changes signs inside the brackets"
:
6y + 2y - 3 = 7 + 6; added 2y to both sides to isolate y on the left
:
8y = 13 + 3; added 3 to both sides to isolate y on the left
:
8y = 16
:
y = 16/8; divide both sides by 8
y = 2
:
:
Check solution in original equation; substitute +2 for x:
3(2y-1)= 7 - 2(y-3)
3(2(2)- 1) = 7 - 2(2 - 3)
3(4 - 1) = 7 - 2(-1); minus times a minus is plus
3 * 3 = 7 + 2
:

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