SOLUTION: please Evaluate: (x^2-3xy^3+2zē)/(x(y^2-z)) when x=-1 y=-2 z=1

Algebra.Com
Question 898204: please Evaluate:
(x^2-3xy^3+2zē)/(x(y^2-z)) when x=-1 y=-2 z=1

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
when x=-1 y=-2 z=1
Plug and Play ex: -3xy^3 = -3(-1)(-8) = -24

RELATED QUESTIONS

Evaluate (3xy^2)/(6z) for x = -3, y = 2 and z =... (answered by ReadingBoosters)
2x+3y+z -3x-2z-7 ( -Z'3-2z+z (-Z 3 is third power))-2z+z __xy-3z_____________ (answered by midwood_trail)
x+3y+2z=1 2z+y-z=2 x+y+z=2 (answered by richwmiller)
x-y+z=1 3x+y-2z=-3... (answered by Alan3354)
solve for x,y and z 1. x+y-2z=5 2. x+z=4 3.... (answered by Alan3354)
can you please help me in solving for x;y;z x+y-2z=5 .........equation 1... (answered by Theo,Edwin McCravy)
x=-y+1 z=2x... (answered by richwmiller)
solve using cramer rule :- 3x+2y+4z=19 2x-y+z=3 6x+7y-z=7 x-y+2z=1 x+y+z=2 2x-y+z=5... (answered by ikleyn)
Solve the system: x-y-z=1 -x-y+2z=-2... (answered by Alan3354)