A pool measuring 10 meters by 20 meters is surrounded by a path of uniform width if the area of the pool and path combined is 416 square meters what is the width of the path
Let UNIFORM width of path, be W
Then width on either end of pool = W + W, or 2W
Area of pool and path = (2W + 10)(2W + 20), and area of pool and path = 416.
Thus, (2W + 10)(2W + 20) = 416
(W - 3)(W + 18) = 0
W, or width of path = m
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