SOLUTION: Please help me solve this equation:
\frac{3x^2–26x+80}{(x-6)(x-4)(x+2)} - \frac{3}{x + 2}
the final answer should be written as:
\frac{a}{x^2+bx+c}
Here a,
Algebra.Com
Question 88520: Please help me solve this equation:
\frac{3x^2–26x+80}{(x-6)(x-4)(x+2)} - \frac{3}{x + 2}
the final answer should be written as:
\frac{a}{x^2+bx+c}
Here a,b and c are ordinary numbers.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
(x-4)(x+2)} - \frac{3}{x + 2})
(x-4)(x+2)} - \left(\frac{(x-6)(x-4)}{(x-6)(x-4)}\right)\left(\frac{3}{x + 2}\right))
Multiply the second fraction by (x-4)}{(x-6)(x-4)})
(x-4)(x+2)} - \left(\frac{3(x-6)(x-4)}{(x-6)(x-4)(x + 2)}\right))
(x-4)(x+2)} - \left(\frac{3(x^2-10x+24)}{(x-6)(x-4)(x + 2)}\right))
Foil
(x-4)(x+2)} - \left(\frac{3x^2-30x+72}{(x-6)(x-4)(x + 2)}\right))
Distribute
-(3x^2-30x+72)}{(x-6)(x-4)(x+2)})
Combine the fractions
(x-4)(x+2)})
Distribute the negative
(x-4)(x+2)})
Combine like terms
}{(x-6)(x-4)(x+2)})
Factor out a 4
(x-4)})
Reduce
Foil the denominator
So
simplifies to
As always, you can verify by graphing the original and the simplified expressions to compare them
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