SOLUTION: Tutor could I please get your help? My problem is: how do I simplify this expression: 3y^2+5yz+2z^2 over 2y^2+3yz+z^2 Thank you!

Algebra ->  Algebra  -> Expressions -> SOLUTION: Tutor could I please get your help? My problem is: how do I simplify this expression: 3y^2+5yz+2z^2 over 2y^2+3yz+z^2 Thank you!      Log On

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Question 86982: Tutor could I please get your help? My problem is: how do I simplify this expression: 3y^2+5yz+2z^2 over 2y^2+3yz+z^2
Thank you!
Found 2 solutions by Earlsdon, stanbon:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify:
%283y%5E2%2B5yz%2B2z%5E2%29%2F%282y%5E2%2B3yz%2Bz%5E2%29 Factor the numerator and the denominator.
%283y%2B2z%29cross%28%28y%2Bz%29%29%2F%282y%2Bz%29cross%28%28y%2Bz%29%29 Cancel the indicated like-factors.
%283y%2B2z%29%2F%282y%2Bz%29 Simplified!

Answer by stanbon(57984) About Me  (Show Source):
You can put this solution on YOUR website!
simplify this expression: 3y^2+5yz+2z^2 over 2y^2+3yz+z^2
-------------------
[3y^2+5yz+2z^2] / [2y^2+3yz+z^2]
= [3y2+3yz+2yz+z^2] / [2y^2+2yz+yz+z^2]
= [3y(y+z)+2z(y+z)] / [2y(y+z)+z(y+z)]
= [(y+z)(3y+2z)] / [(y+z)(2y+z)]
=(3y+2z) / (2y+z)
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Cheers,
Stan H.