SOLUTION: Tutor could I please get your help?  My problem is:  how do I simplify this expression:  3y^2+5yz+2z^2 over 2y^2+3yz+z^2  
Thank you!
Algebra.Com
Question 86982:  Tutor could I please get your help?  My problem is:  how do I simplify this expression:  3y^2+5yz+2z^2 over 2y^2+3yz+z^2  
Thank you! 
Found 2 solutions by  Earlsdon, stanbon:
Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
 Simplify:
 Factor the numerator and the denominator.
 Cancel the indicated like-factors.
 Simplified! 
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
 simplify this expression: 3y^2+5yz+2z^2 over 2y^2+3yz+z^2 
-------------------
[3y^2+5yz+2z^2] / [2y^2+3yz+z^2]
= [3y2+3yz+2yz+z^2] / [2y^2+2yz+yz+z^2]
= [3y(y+z)+2z(y+z)] / [2y(y+z)+z(y+z)]
= [(y+z)(3y+2z)] / [(y+z)(2y+z)]
=(3y+2z) / (2y+z)
========================
Cheers,
Stan H. 
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