SOLUTION: When (67th + 67) is divided by 68, the remainder is: a) 1 b) 63 c) 66 d) 67. The answer is 66. But I dont know how it comes. Please elaborate it.

Algebra ->  Expressions -> SOLUTION: When (67th + 67) is divided by 68, the remainder is: a) 1 b) 63 c) 66 d) 67. The answer is 66. But I dont know how it comes. Please elaborate it.       Log On


   

Question 861360: When (67th + 67) is divided by 68, the remainder is:
a) 1 b) 63 c) 66 d) 67.
The answer is 66. But I dont know how it comes. Please elaborate it.

Answer by ben720(159) About Me  (Show Source):
You can put this solution on YOUR website!
The remainder is whatever the 68 doesn't cover. Because 67 is less than 68, 2 67s is less than 2 68s. Therefore, only one 68 will fit into 67+67. In algebraic form:
67%2B67=68%2Bx
Because 67 is only one less than 68, when you subtract 68 from both sides, it becomes 67-1, or 66.
In non-algebraic form:
The answer is 67%2B67-68
67-1
66