SOLUTION: Solve for the value of k that will make the roots of the function be real and equal: f(x)=(K-2)x^(2)+3Kx+3K+6

SOLUTION: Solve for the value of k that will make the roots of the function be real and equal: f(x)=(K-2)x^(2)+3Kx+3K+6

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Question 765365: Solve for the value of k that will make the roots of the function be real and equal: f(x)=(K-2)x^(2)+3Kx+3K+6
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Exercise is for using the discriminant.

, the discriminant.

You want the discriminant to be 0 to make f(x) have only one solution. This solution will be real.

OR
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