SOLUTION: Given x3-64 = ( x+a ) ( x2+bx+c ) what are the values of a, b and c. Enter your answer as a list [in brackets], in the form: [a, b, c]

SOLUTION: Given x3-64 = ( x+a ) ( x2+bx+c ) what are the values of a, b and c. Enter your answer as a list [in brackets], in the form: [a, b, c]

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Question 73734: Given
x3-64 = ( x+a ) ( x2+bx+c )

what are the values of a, b and c. Enter your answer as a list [in brackets], in the form: [a, b, c]

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Using the difference of cubes forumla:

We can see that m=x and n=4 (since 4^3=64) So a=-n,b=n, and c=n^2. Since n=4, a=-4, b=4, and c=16 (just match the variables). So the answer is [-4,4,16].
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