SOLUTION: The expression f(x)=x^3+ax^2+bx-6 is exactly divisible by (x-1), and has a
remainder of 20 when it is divided by (x-2). Calculate the value of a and b.
Algebra.Com
Question 695456: The expression f(x)=x^3+ax^2+bx-6 is exactly divisible by (x-1), and has a
remainder of 20 when it is divided by (x-2). Calculate the value of a and b.
Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!
f(1) = 0 therefore a + b = 5
f(2) = 20 therefore 4a + 2b + 2 = 20, transpose 2 then divide by -2
The result is -2a - b = -9, add to a + b = 5
The result is -a = -4, therefore a = 4 and b = 1.
Answer: a = 4 and b = 1
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