SOLUTION: Can someone assist in helping with this problem?
3y^2 - 2
_________
3y^2 + 10y - 8
minus
y + 10
________
3y^2 + 10y - 8
minus
y^2 - 6y
_________
3y^2 + 10y - 8
Algebra.Com
Question 675272: Can someone assist in helping with this problem?
3y^2 - 2
_________
3y^2 + 10y - 8
minus
y + 10
________
3y^2 + 10y - 8
minus
y^2 - 6y
_________
3y^2 + 10y - 8
Equals =
Found 3 solutions by ReadingBoosters, stanbon, MathLover1:
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
...
...
distribute the negatives
...
Combine like terms
...
.....................
Delighted to help.
-Reading Boosters
Website: www.MyHomeworkAnswers.com
Wanting for others what we want for ourselves.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(3y^2 - 2)/(3y^2 + 10y - 8)
- (y + 10)/(3y^2 + 10y - 8)
- (y^2 - 6y)/(3y^2 + 10y - 8)
-------------------------------------
The denominators are all the same, so combine the numerators
over the common denominator::
---
= [3y^2-2-y-10-y^2+6y]/(3y^2+10y-8)
----
= (2y^2 +5y -12)/(3y^2+10y-8)
----
Factor:
= (2y^2+8y-3y-12)/(3y^2+12y-2y-8)
-----
= (2y(y+4)-3(y+4))/(3y(y+4)-2(y+4))
-----
= [(y+4)(2y-3)]/[(y+4)(3y-2)]
-------
= (2y-3)/(3y-2)
========================
cheers,
Stan H.
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
............common denominator is
=
=
=.........factor completely nominator (replace with ) and denominator (replace with )
=....group
=
=
=
=
=
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