SOLUTION: solve (x-2)^2-2=-x+3

Question 665886: solve (x-2)^2-2=-x+3
Answer by Jacky C(3) (Show Source): You can put this solution on YOUR website!
in the exponents 2-2 is equal to 0 so
(x - 2)^0 = -x + 3
since -x contains the variable to solve move it for the lefth hand side of the equation by adding x both sides
(x - 2)^0 +x = 3
anything raised to the 0th power is 1
(1)+ x = 3
reorder the polynomial by alphabetically from the left to right
x + 1 = 3
so 1 don't have the variable to solve the move them from the right hand
x= -1 + 3 solve
the answer is x=2

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