SOLUTION: k + 4 + k^2 -5k + 8
------- ------ ----------- --- =
k + 1 1 - k k^2 -1
Algebra.Com
Question 636615: k + 4 + k^2 -5k + 8
------- ------ --------------- =
k + 1 1 - k k^2 -1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
k 4 k^2 -5k + 8
------- + ------ + ------------
k + 1 1 - k k^2 -1
-------------------------
Rewrite:
k 4 k^2 -5k + 8
------- - ------ + ------------
k + 1 k - 1 k^2 -1
lcm = (k^2-1)
-----
Rewrite each fraction with the lcm as its denominator:
------
[k(k-1) -4(k+1) +k^2-5k+8]/[k^2-1]
------
[k^2-k-4k-4+k^2-5k+8]/[k^2-1]
------
[2k^2-10k+8]/[k^2-1]
----
= [2(k^2-5k+4)]/[k^2-1]
-----
= [2(k-4)(k-1)]/[(k+1)(k-1)]
-----
= [2(k-4)]/[k+1]
=====================
Cheers,
Stan H.
====================
RELATED QUESTIONS
Find the Value of K
K.......3+K.........-10
1-K......2-K......... 5 = 48
2... (answered by Edwin McCravy)
What is answer in Lowest terms ((5+5k)/4) + ((1+k)/8)
Work done:
((5+5k)/4) +... (answered by Theo,JBarnum)
(k-3)/(k-2)-(k-4)/(k-1)=(3k+2)/(k^2-3k+2) (answered by Fombitz)
Tan^4(k)-sec^4(k)=1-sec^2(k) (answered by jsmallt9)
-4(k-2)+3(k-1)=7 (answered by jim_thompson5910)
k^2+5k=2 (answered by 55305)
5k/2-k = -7 (answered by ankor@dixie-net.com)
k k
- + - =
4... (answered by ankor@dixie-net.com)
5-9k+1+k-2(7-k) (answered by rchill)