SOLUTION: pretty sure i'm in the wrong place, but couldn't find a subject to suit find derivatives of y=x^2-3x+1/x

Question 568984: pretty sure i'm in the wrong place, but couldn't find a subject to suit
find derivatives of y=x^2-3x+1/x
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
looks like calculus.
i didn't see a category for calculus.
i put it in evaluation of expressions because this is an expression and you are evaluating it by finding the derivative.
might be a stretch, that was my best guess.
i don't remember a lot about calculus, but i do remember the rules are:
derivative of ax^n equals n * a * x^(n-1)
a is the coefficient.
x is the variable.
using those rules, i would say the derivative of x^2 - 3x + 1/x would be calculated as follows:
rewrite the equation as the equivalent expression of:
x^2 - 3x + 1x^(-1)
take the derivative following the rules to get:
2x - 3 - 1x^(-2) which results in:
2x - 3 - 1/x^2 which can be rewritten as:
2x - 1/x^2 - 3
i found a calculator on the web that differentiates equations.
that calculator can be found at:
http://freemathhelp.com/derivative-calculator.php?diff=x^2-3*x%2B1%2Fx&var=x&Submit=Get+Derivative
it gave me the same answer.
i believe this calculator needs you to explicitly enter multiplication operators.
your equation of x^2 - 3x + 1/x should be entered as:
x^2 - 3*x + 1/x
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