SOLUTION: 4w^3/28w^2
Algebra.Com
Question 568788: 4w^3/28w^2
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
4w^3/28w^2 = (4/28)(w^3/w^2) = (1/7)(w^(3-2)) = (1/7)w^1 = w/7
So 4w^3/28w^2 = w/7 for all values of w where w is not equal to zero
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