SOLUTION: Can someone help me on this problem. I have gotten two different results and not sure which was is right. The length of a rectangle is 2 cm more than twice its width. f the

Question 55097: Can someone help me on this problem. I have gotten two different results and not sure which was is right.
The length of a rectangle is 2 cm more than twice its width. f the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
Thanks,
Sher
Found 3 solutions by rchill, funmath, anjulasahay:
Answer by rchill(405)   (Show Source): You can put this solution on YOUR website!
Let w represent the width, then (2w+2) is the length ("2 more than twice its width"). Because a rectangle's perimeter is 2(l+w), your rectangle's perimeter becomes . Expanding the equation gives us which further expands to . Solving for w gives us , which means the length is which is 18. To prove that the rectangle is 8 by 18, it's perimeter should be 52: 8+8+18+18=52. Yeah!
Answer by funmath(2933)   (Show Source): You can put this solution on YOUR website!
Hi Sher,
The length of a rectangle is 2 cm more than twice its width. f the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
Let width (W)=x
Then the length (L)=2x+2
The Perimeter (P)=52 cm
The formula for the perimeter of a rectangle is:

52=2(x)+2(2x+2)
52=2x+2(2x)+2(2)
52=2x+4x+4
52=6x+4
52-4=6x+4-4
48=6x

8=x
The width:x=8 cm
The Length: 2x+2=2(8)+2=16+2=18 cm
:
Check:

52=2(8)+2(18)
52=16+36
52=52 Looks like we're right!!!
Happy Calculating, Sher!!!
funmath

Answer by anjulasahay(30)   (Show Source): You can put this solution on YOUR website!
Can someone help me on this problem. I have gotten two different results and not sure which was is right.
The length of a rectangle is 2 cm more than twice its width. f the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle
ans:
let length of the rectangle = l
width of the rectangle = w
hence according to the question ,

l = 2+2*w ----I
and perimeter of rectangle = 2(l+w)
= 2((2+2w)+w) (putting l from I)
=2(2+3w)=52
or 2+3w = 21
or 3w=19
or w = 19/3
hence l = 2+2*19/3 = 44/3

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