SOLUTION: the perimeter of a pentagon (4x +4) is three times the perimeter of a triangle (x + 3) find x. also calculate perimeters of both and a regular octagon has the same perimeter what i

Question 546850: the perimeter of a pentagon (4x +4) is three times the perimeter of a triangle (x + 3) find x. also calculate perimeters of both and a regular octagon has the same perimeter what is lenth of each side? i dont understand this. i tried 3(4x+4) an got 12x + 12 am i on theright track?
Answer by boilpoil(127) (Show Source): You can put this solution on YOUR website!
No, you are on the wrong track. Perimeter of pentagon (4x+4) is(=) 3 times(3(?)) the perimeter of a triangle(3(x+3)).

So, according to the previous analysis:

4x+4=3(x+3)
4x+4=3x+9
x=5

Perimeter of pentagon
=4(5)+4
=20+4
=24

Perimeter of triangle
=5+3
=8

If the perimeter of the octagon equals the perimeter of pentagon(P) OR triangle(T)
P=24�8
=3

T=8�8
=1
***Does not know the what the perimeter of the octagon equals so I do both for you***

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