# SOLUTION: f(x) = (1 + x)/x g(x) = 1/(1 - x) h(x) = 1/(1 + x) If so, (g o h)(x) = a. x b. 2 - x c. -x d. x/(2x + 1) e. (1 - x)/(2 - x) f. (1 + x)/x g. (2 - x)/(1 - x)

Algebra ->  Expressions -> SOLUTION: f(x) = (1 + x)/x g(x) = 1/(1 - x) h(x) = 1/(1 + x) If so, (g o h)(x) = a. x b. 2 - x c. -x d. x/(2x + 1) e. (1 - x)/(2 - x) f. (1 + x)/x g. (2 - x)/(1 - x)       Log On

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 Algebra: Evaluation of expressions, parentheses Solvers Lessons Answers archive Quiz In Depth

 Question 50554: f(x) = (1 + x)/x g(x) = 1/(1 - x) h(x) = 1/(1 + x) If so, (g o h)(x) = a. x b. 2 - x c. -x d. x/(2x + 1) e. (1 - x)/(2 - x) f. (1 + x)/x g. (2 - x)/(1 - x) h. (1 - x)/x i. 2 + x j. none of theseAnswer by rapaljer(4670)   (Show Source): You can put this solution on YOUR website!g(x) = 1/(1 - x) h(x) = 1/(1 + x) (g o h)(x) = g[ f(x) ] g[ f(x) ] = This looks a LOT worse than it really is!! It's a complex fraction, and I have a LOT of these worked out on my Math in Living Color pages of my website! I'm more comfortable in that format, and they are in "Living Color"! Multiply both numerator and denominator by the LCD which is (1+x). g[ f(x) ] = g[ f(x) ] = g[ f(x) ] = g[ f(x) ] = , which is the f) answer. R^2 at SCC