SOLUTION: Can someone help me on this?
Suppose that the temperature outside is dropping at a constant rate. At noon, the temperature is 70 degrees F and it drops to 58 degrees F at 5:0
Algebra.Com
Question 46637: Can someone help me on this?
Suppose that the temperature outside is dropping at a constant rate. At noon, the temperature is 70 degrees F and it drops to 58 degrees F at 5:00 P.M. How much did the temperature change each hour?
Thanks,
Lyn
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
70-58 or a drop of 12 degree in 5 hour thus -12/5=-2.4 degrees per hour
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