SOLUTION: the length of the rectangle is 3 meters more than its width.If the perimeter is 54 meters,what are its dimensions?
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You can put this solution on YOUR website! the length of the rectangle is 3 meters more than its width.If the perimeter is 54 meters,what are its dimensions?
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Let L = W+3
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Perimeter = 2(L+W)
Substitute and solve for "W":
54 = 2(W+3 + W)
27 = 2W+3
2W = 24
Width = 12 meters
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Solve for "L":
Length = W + 3
Length = 15 meters
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Cheers,
Stan H.
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