SOLUTION: The perimeter of a rectangular sign is not to exceed 50ft. The length is to be twice the width. What widths will meet these conditions? I think it starts like this: l=2w≤50
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Question 440619: The perimeter of a rectangular sign is not to exceed 50ft. The length is to be twice the width. What widths will meet these conditions? I think it starts like this: l=2w≤50
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangular sign is not to exceed 50ft. The length is to be twice the width. What widths will meet these conditions? I think it starts like this: l=2w≤50
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Let the width be "w".
Then the length is "2w"
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Perimeter = 2(length + width)
2(2w + w) <= 50
3w <= 25
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width <= 25/3 ft
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Cheers,
Stan H.
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