You can put this solution on YOUR website!
This looks like a neat problem. Let's rearrange it and see if this helps sort it out, and subtract 29 from each side while you are at it:
Notice that you can "complete the square" (remember "half and square"??) on each of these quantities, by adding 4 on the first blank and 25 on the second blank.
Since the sum of two squares equals zero, this means that each quantity squared must equal zero!
x+y-2=0 and x+3y-5=0
Solve by elimination:
So, 2y = 3,
NOW, you wanted 2y^2 + xy=
R^2 at SCC