SOLUTION: logbx + logb(x+2)-logb8
assume that x, y amd x are positive numbers. Use the properties of logarithms to write each expression as the logarithm of one quantity
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Question 391739: logbx + logb(x+2)-logb8
assume that x, y amd x are positive numbers. Use the properties of logarithms to write each expression as the logarithm of one quantity
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
logbx + logb(x+2)-logb8
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= logb[x(x+2)/8]
----
= logb[(x^2+2x)/8]
======================
Cheers,
Stan H.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi,
 )
 )
-log_b8 )
/8 )
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