SOLUTION: if x=12,y=8 and z=6
find the values of:
3x+5y+4z
Algebra.Com
Question 350566: if x=12,y=8 and z=6
find the values of:
3x+5y+4z
Answer by benazir.sj@gmail.com(109) (Show Source): You can put this solution on YOUR website!
3x+5y+4z if x=12,y=8 and z=6
solution:
substitute the values of x,y,z in the given equation
3x+5y+4z
=3*12+5*8+4*6
=36+40+24
=100
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