SOLUTION: evaluate the function
f(x)=(1/3)^-x+1 at x=3
Algebra.Com
Question 242711: evaluate the function
f(x)=(1/3)^-x+1 at x=3
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
f(x)=(1/3)^-x +1
I'm assuming that the exponent is -x, then the +1 is separate from the exponent.
f(3)= (1/3)^-3 +1
f(3)= 3^3+1
f(3)=27+1
f(3)=28
Dr. Robert J. Rapalje
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