SOLUTION: -3-4(t-5)=-2(t+3)+11 0.08x+0.5(x+100)=73.2

Question 184494: -3-4(t-5)=-2(t+3)+11
0.08x+0.5(x+100)=73.2
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
-3-4(t-5)=-2(t+3)+11
-3-4T+20=-2T-6+11
-4T+2T=-6+11+3-20
-2T=-12
T=-12/-2
T=6 ANS.
PROOF:
-3-4(6-5)=-2(6+3)+11
-3-24+20=-2*9+11
-7=-18+11
-7=-7
-----------------------
0.08x+0.5(x+100)=73.2
.08X+.05X+50=73.2
..58X=73.2-50
.58X=23.2
X=23.2/.58
X=40 ANS.
PROOF:
.08*40+.05(40+100)=73.2
3.2+.5*140=73.2
3.2+70=73.2
73.2=73.2

RELATED QUESTIONS
-3-4(t-5)=-2(t+3)+11 (answered by jim_thompson5910)

-3-4(t-5)=-2(t+3)+11 (answered by jim_thompson5910)

-3-4(t-5)=2(t+3)+11= (answered by checkley77)

-3 - 4 (t-5) = -2... (answered by JBarnum)

-3 -4(t -5)=-2(t + 3) +... (answered by jim_thompson5910)

-3-4(t-5)=-2(t+3)+11 (answered by robertb)

t^3-4t^2-3t+5=0 (answered by user_dude2008)

6(t+2)-4(t-3)=0 (answered by baholik06)

6(t+2)-4(t-3)=0 (answered by checkley77)