SOLUTION: Is -1 a solution of 4square -1=4y + 3 ?
I have trouble working these I do understand you have to do to the same side as you do to the other. please understand I am a 40 year old
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Question 181299This question is from textbook Beginning Algebra with applications
: Is -1 a solution of 4square -1=4y + 3 ?
I have trouble working these I do understand you have to do to the same side as you do to the other. please understand I am a 40 year old going back to school and never had algebra in high school at all. If I had only know I would have paid alot more attention in school and taken college bound courses.
thanks for your help and God Bless
This question is from textbook Beginning Algebra with applications
Found 2 solutions by Mathtut, solver91311:
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
well lets hope I do the equation the way it is suppose to be
:
your just plugging in the value of -1 into the variable y and checking to see if this makes a true or false statement
:
:
:
:
since 15 does not equal -1.....-1 is NOT a solution. If the equation is different that this email me the correct equation..thanks Mathtut
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Do you mean:
?
If so, then to determine if a value is a solution to an equation, you simply substitute that value for the variable and do the arithmetic to determine if you have a true statement or not, thus:
 + 3 \ \ \Rightarrow \ \ 16 - 1 = -4 + 3 \ \ \Rightarrow \ \ 15 = -1)
is clearly a false statement.
(Unless you are talking about Financial System bailouts and such).
Substituting -1 for the variable y does not result in a true statement, therefore -1 is not a solution to the equation.
Just for fun, let's see what the solution set does contain:
.
Now add -3 to both sides:
 = 4y + 3 + (-3) \ \ \Rightarrow \ \ 12 = 4y)
.
Now multiply both sides by 
:
 = 4y\left(\frac{1}{4}\right) \ \ \Rightarrow \ \ 3 = y \ \ \Rightarrow \ \ y = 3)
.
Hence, the solution set contains the single element 3.
John
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