SOLUTION: After fully simpifying the expression
2*x^2+7*x+3 over x^2+3*x-4 divided by x^2+7*x+12 over 2*x^2-3*x+1
The numerator is (2*x+1)*(2*x-1)
The denominator is
Remember to
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Question 178214: After fully simpifying the expression
2*x^2+7*x+3 over x^2+3*x-4 divided by x^2+7*x+12 over 2*x^2-3*x+1
The numerator is (2*x+1)*(2*x-1)
The denominator is
Remember to invert and multiply, factor and cancel
Ok, I can get the numberator, but I am not sure how to get the denominator, any help with is problem will be greatly appreciated. Thank you.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
First thing is to factor each of the polynomial expressions:
(x + 3))
(x - 1) )
(x + 4) )
(x - 1) )
So the expression becomes:
(x + 3) }{ (x + 4)(x - 1) }}{\frac { (x + 3)(x + 4) }{ (2x - 1)(x - 1) }})
Now invert and multiply:
(x + 3) }{ (x + 4)(x - 1) }\right) \left({\frac { (2x - 1)(x - 1) }{ (x + 3)(x + 4) } \right) = \frac { (2x + 1)(x + 3) (2x - 1)(x - 1)}{ (x + 4)(x - 1)(x + 3)(x + 4) } )
Eliminate factors common to both numerator and denominator:
(2x - 1) }{ (x + 4) (x + 4)} )
The numerator binomials are a conjugate pair, so the product is the difference of 2 squares, and the product of the denominator can be found by applying FOIL:
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