SOLUTION: Placing planks at equel length end to end, jewels found that three planks where one foot short of the portch length, while four planks were two feet to long. How long was each plan

Algebra ->  Algebra  -> Expressions -> SOLUTION: Placing planks at equel length end to end, jewels found that three planks where one foot short of the portch length, while four planks were two feet to long. How long was each plan      Log On

Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 158526This question is from textbook Algerbra 1
: Placing planks at equel length end to end, jewels found that three planks where one foot short of the portch length, while four planks were two feet to long. How long was each plank?This question is from textbook Algerbra 1

Answer by stanbon(48545) About Me  (Show Source):
You can put this solution on YOUR website!
Placing planks at equal length end to end, jewels found that three planks where one foot short of the porch length, while four planks were two feet to long. How long was each plank?
-------------------
EQUATION:
porch length = porch length
3p+1 = 4p-2
p = 3 ft.
Cheers,
Stan H.