SOLUTION: a2+5ab2-3b2+7a2b-ab2=a2
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Question 158021This question is from textbook colleg elementary algebra
: a2+5ab2-3b2+7a2b-ab2=a2
This question is from textbook colleg elementary algebra
Answer by integral13(8) (Show Source): You can put this solution on YOUR website!
a^2+5ab^2-3b^2+7a^2b-ab^2=a^2
Take out an (a)
a(a+5b^2-3b^2+7ab-b^2)=a(a)
Cancel out the (a's)
a+5b^2-3b^2+7ab-b^2=a
Subtract 5b^2 3b^2 and b^2
a+b^2+7ab=a
Subtract a on both sides
b^2+7ab=0
Transfer 7ab on the other side of the equal sign
b^2=-7ab
Take out a b from both sides
b(b)=(-7a)b
Cancel out the b's
b=-7a is your final answer
Hope that helps!!!
integral13
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