SOLUTION: -20-3x+3x^2=0
I can't seem to find the right way to factor it!
Algebra.Com
Question 152073: -20-3x+3x^2=0
I can't seem to find the right way to factor it!
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Perhaps that is because the trinomial is not factorable...in other words, it's prime.
Let's rearrange the trinomial so that it's in standard form:
The factors, if there were any, would take the form:
and you need to have m*n = -20 and 3n+m = -3
The factors of -20 are:
-20 = -1*20 or 1*(-20) and 3(-1)+20 = 17, 3(1)+(-20) = -17
-20 = -2*10 or 2*(-10) and 3(-2)+10 = 4, 3(2)+(-10) = -4
-20 = -4*5 or 4*(-5) and 3(-4)+5 = -7, 3(4)+(-5) = 7
So, as you can see, there is no way to get a -3 from combining the factors of -20.
The trinomial is prime!
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