SOLUTION: find three consecutive integers such that 3 times the sqaure of the first exceeds the product of the other two by 25

Question 127004: find three consecutive integers such that 3 times the sqaure of the first exceeds the product of the other two by 25
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
First integer: x
Second integer: x + 1
Third integer: x + 2

3 times the square of the first:
The product of the other two:

3 times the square of the first exceeds the product of the other two by 25:

So or . We can exclude the first root because it is not an integer. So the first integer is -3, the second would be -2, and the third, -1.

Check:

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