SOLUTION: The base of an isosceles triangle is 12 in. less than the length of the equal sides. If the perimeter of the triangle is 39 in., find the length of each sides.
Algebra.Com
Question 122181: The base of an isosceles triangle is 12 in. less than the length of the equal sides. If the perimeter of the triangle is 39 in., find the length of each sides.
Answer by jasonlin00(6) (Show Source): You can put this solution on YOUR website!
17 for each side, and 5 for the base
RELATED QUESTIONS
The base of an isosceles triangle is 12 in. less than the length of the equal sides. If... (answered by Edwin McCravy)
The base of an isosceles triangle is 12 in. less than the length of the equal sides. If... (answered by checkley75)
The base of an isosceles triangle is 12 in. less than the length of the equal sides. If... (answered by Nate)
the base of an isosceles triangle is 3 cm less than the length of the equal sides. if the (answered by elima4)
The base of an isosceles triangle is 8 in. less than the length of the equal sides. If... (answered by checkley71)
The base of an isosceles triangle is 4 in. less than the length of the equal sides. If... (answered by Earlsdon)
The base of an isosceles triangle is 11 in. less than the length of the equal sides. If... (answered by rajagopalan)
The base of an isosceles triangle is 8 in. less than the length of the equal sides. If... (answered by Fombitz)
The base of an isosceles triangle is 1 in. less than the length of one of the equal sides (answered by mananth)