SOLUTION: Find 3 consecutive numbers such that the sum of the 1st and 3rd numbers exceeds the 2nd number by 10.
Algebra.Com
Question 1192114: Find 3 consecutive numbers such that the sum of the 1st and 3rd numbers exceeds the 2nd number by 10.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find 3 consecutive numbers such that the sum of the 1st and 3rd numbers exceeds the 2nd number by 10.
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If you mean integers:
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Use n-1, n and n+1
--
2n = n+10
n = 10
---> 9, 10 & 11
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