SOLUTION: A. Let g(t) be the solution of the initial value problem 4t(dy/dt)+y=0, t>0, with g(1)=1. Find g(t). g(t)= My answer is t^(-1/4), is correct. B. Let f(t) be the solution of

Question 1184045: A. Let g(t) be the solution of the initial value problem
4t(dy/dt)+y=0, t>0,
with g(1)=1.
Find g(t).
g(t)= My answer is t^(-1/4), is correct.
B. Let f(t) be the solution of the initial value problem
4t(dy/dt)+y=t^4
with f(0)=0.
Find f(t).
f(t)= My answer is 1/4t^(1/3), it's wrong
C. Find a constant c so that
k(t)=f(t)+cg(t)
solves the differential equation in part B and k(1)=14.
c=
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
B. The answer is . This satisfies the IV condition of f(0) = 0, and the D.E., as
.

C. ===>
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