SOLUTION: Consider the initial value problem y′=3y^2,y(0)=y0. For what value(s) of y0 will the solution have a vertical asymptote at t=2 and a t-interval of existence −∞<t<2? y0

Question 1184040: Consider the initial value problem
y′=3y^2,y(0)=y0.
For what value(s) of y0 will the solution have a vertical asymptote at t=2 and a t-interval of existence −∞ y0= My answer is 1/21 but it's wrong.
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
The particular value that will satisfy the IVP is .
The function that will satisfy the IVP is .

Note that at t = 2 there is a vertical asymptote because the denominator is zero there.
Also the maximal interval of existence is (, 2), since the initial condition can be found in this interval, and not at t > 2.
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