SOLUTION: Find the seventh term of (x^2-2)^9

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Question 1163160: Find the seventh term of (x^2-2)^9
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52847)   (Show Source): You can put this solution on YOUR website!
.

The binomial expansion is this formula


     =  +  +  +  + . . . +  + 


In our case,  n = 9,  a = x^2,  y = -2.  Therefore, the general term of the binomial expansion in our case is  


    , k = 0, 1, 2, 3, 4, 5, . . . 


Then the 7-th term is at k = 6 


     =  =  = .    ANSWER

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Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!
Find the seventh term of (x^2-2)^9
To find a SPECIFIC TERM of a binomial expansion, we use the formula: ,      

                                                                     where: 

We then get: 7th term of  

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