SOLUTION: Find values of n in the equation
2x^2 - 5(n-1)x +12=0 if the
two roots are consecutive.
Algebra.Com
Question 1118753: Find values of n in the equation
2x^2 - 5(n-1)x +12=0 if the
two roots are consecutive.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
Looking at a few factorization trial combinations for the quadratic lead to
and these roots are -3 and -2, which are consecutive integers.
Steps from that and then compare to the given quadratic expression:
from which corresponding parts give
Find n from that last equation.
Answer by ikleyn(52847) (Show Source): You can put this solution on YOUR website!
.
Find values of n in the equation
2x^2 - 5(n-1)x +12=0
if the two roots are consecutive .
~~~~~~~~~~~~~~~~~~~~~~~~~~
1. Why you can not write the condition accurately and correctly ? Why I should edit your writing ?
2. The answer by @josgarithmetic in uncompleted.
The complete answer is THIS:
There are two solutions. One solution is: the roots are 2 and 3, and n = 3.
The other solution is: the roots are -3 and -2, and n = -1.
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