SOLUTION: How to factor 64x^6 - 1 completely?
4/3(6x-3) = 3/4(8x-12)
Solve for x:
-2/9x + 2/45 = 2/5
Algebra.Com
Question 1109657: How to factor 64x^6 - 1 completely?
4/3(6x-3) = 3/4(8x-12)
Solve for x:
-2/9x + 2/45 = 2/5
Answer by josgarithmetic(39626) (Show Source): You can put this solution on YOUR website!
Maybe you really mean, ?
Look at the factors on each side carefully,...
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EASIER THAN THAT:
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You can figure out the last equation, and the first expression you asked for factorization shows Difference Of Squares.
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