SOLUTION: Find the gradient of the tangent where t = 3, given x=(2t-5)(t+1)^3

SOLUTION: Find the gradient of the tangent where t = 3, given x=(2t-5)(t+1)^3

Algebra.Com

Question 1088613: Find the gradient of the tangent where t = 3, given x=(2t-5)(t+1)^3
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
The slope(gradient) of a curve is equal to the value of the derivative at that point.
So using the chain rule,

So then when ,

Work that out for your answer.

RELATED QUESTIONS
Find the coordinates of the point where the line with parametric equations: x=1-t,... (answered by Edwin McCravy)

Find the tangent to each curve at the point where t = 3: x = 5(t)^2, y = 10t... (answered by greenestamps)

Suppose cos(t)=-1/3 and sin(t)<0 Use appropriate identities to find each of the... (answered by KMST)

Given h(t)=2t^2-t, find the average rate of change from t=3 to t=6 (answered by ikleyn)

Find dy/dx and calculate the gradient of the tangent to the curve y=1/square root 1+x at... (answered by Alan3354)

{{{ (t^2-1)/(t^2-4) }}} + {{{ (9t+9)/(4t+12) }}} * {{{ (2-t)/(t^2+2t-3) }}} The back... (answered by Alan3354,greenestamps,MathTherapy)

Rewrite the rational expression with the given denominator -2t/3(t-5) = ?/6(t-5) (answered by josgarithmetic)

Determine the gradient of the tangent to the following curve where x=2: y=(x^2 -3)(x+3) (answered by Cromlix)

5(t-3)=2t (answered by rfer)