SOLUTION: I need help solving these equations- the last two I need to solve and graph. getting started on the 1st one I got as far as 21k-15 =12 I am thinking that the solution would be 3k.

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Question 104811: I need help solving these equations- the last two I need to solve and graph. getting started on the 1st one I got as far as 21k-15 =12 I am thinking that the solution would be 3k. On the 2nd question- arrived at: 15-5x < 3x-9, where do I go from here? Last: Not sure how to solve the last one. Please help!

3/4 (7k - 5)=12

5(3-x)< 3(x-3)

3x + 2 < 5''.

Answer by edjones(7311) (Show Source):
You can put this solution on YOUR website!
3/4 (7k - 5)=12
21k-15=48 multiply 4 times each side to get rid of fractions.
21k=63 add 15 to each side.
k=3 divide each side by 21.
.
5(3-x)< 3(x-3)
15-5x<3x-9
24<8x add 5x+9 to each side
3 .
3x+2<5
3x<3 subtract 2 from each side.
x<1 divide each side by 3.
.
Ed