SOLUTION: {{{(a(x+1)+b(x-1))/(x-2)=2+(1/(x-2))}}}
The equation above is true for all values of x≠2, where a and b are constats. What is the value of a?
A) -1/2
B) 2
C) 3
D) 4
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-> SOLUTION: {{{(a(x+1)+b(x-1))/(x-2)=2+(1/(x-2))}}}
The equation above is true for all values of x≠2, where a and b are constats. What is the value of a?
A) -1/2
B) 2
C) 3
D) 4
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Question 1043622:
The equation above is true for all values of x≠2, where a and b are constats. What is the value of a?
A) -1/2
B) 2
C) 3
D) 4 Found 2 solutions by jim_thompson5910, rothauserc:Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! 2 + ( 1 / (x-2) ) = (2x-3) / (x-2), then
:
a(x+1) + b(x-1) = 2x-3
:
ax+a +bx-b = 2x-3
:
we have two equations in 2 unknowns
:
1) ax +bx = 2x
2) a -b = -3
:
solve 2) for b
:
b = a +3
:
substitute for b in equation 1)
:
ax +(a+3)x = 2x
:
2ax = -x
:
************
a = -0.5
answer is A)
************
:
check our answer
a = -0.5, then b = -0.5 +3 = 2.5
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substitute for a and b in the original equation
:
(-0.5(x+1) + 2.5(x-1)) / (x-2) =
:
(-0.5x -0.5 +2.5x -2.5) / (x-2) =
:
(2x - 3) / (x-2) = 2 + ( 1 / (x-2) ) = (2x -3) / (x-2)
:
our answer checks :-)
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