SOLUTION: f(x)=x^2-6x+12
g(x)=k
In the equation above, f(x)>=g(x) for all real numbers x. If k is a constant, what is the maximum value of k?
Algebra.Com
Question 1043305: f(x)=x^2-6x+12
g(x)=k
In the equation above, f(x)>=g(x) for all real numbers x. If k is a constant, what is the maximum value of k?
Answer by josgarithmetic(39623) (Show Source): You can put this solution on YOUR website!
Maybe better, expect k to be the vertex, minimum value for f(x).
to complete-the-square;
Vertex is (3,3).
The line g(x)=k must be no higher than y=3. The MAXIMUM value for k is 3.
RELATED QUESTIONS
f (x) = kg(x) + 2
The function f above is defined in terms of another
function g for... (answered by Theo)
How do I find all values of x for which f(x)>g(x) and when f(x) (answered by Fombitz)
For what value of k is the function g(x)= x^2+5, x<4 and 2x-k, x>4 continuous on all real (answered by Fombitz)
Let f(x) = 3x^2 - 4x. Find the constant k such that f(x) = f(k - x) for all real numbers... (answered by richard1234)
Let f(x) = 3x^2 - 4x. Find the constant k such that f(x) = f(k - x) for all real numbers (answered by reviewermath)
Let f(x) = 3x^2 - 4x. Find the constant k such that f(x) = f(k - x) for all real numbers (answered by ikleyn)
x –1,1,2
f(x) 729,9,1
Q65 The table above shows some values for the function... (answered by greenestamps)
If (x)= x^2+1 and g(x)=x-1 for all real numbers x, for what real number does f(g(-a))=... (answered by ikleyn)
Determine the equation for {{{ h(x) }}} , where {{{ h(x)=k*(g-f) }}}
{{{ f(x)= sqrt... (answered by stanbon)