SOLUTION: {{{((3+i)/(2-i))(a+bi)=1}}} In the equation above, a and b are constants. If {{{i=sqrt(-1)}}}. what is the value of a?

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Question 1043213: In the equation above, a and b are constants. If . what is the value of a?
Found 2 solutions by stanbon, ikleyn:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
((3+i)/(2-i))(a+bi)=1 In the equation above, a and b are constants. If i=sqrt(-1). what is the value of a?
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(6-3i+2i+1)(a+bi) = 1
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(7-i)(a+bi) = 1 + 0i
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7a+b + (7b-a)i = 1 + 0i
-------
7a + b = 1
-a + 7b = 0
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Modify for elimination::
7a + b = 1
-7a + 49b = 0
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Add and solve for "b"::
50b = 1
b = 1/50
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Solve for "a":
7a + b = 1
7a = (49/50)
a = 7/50
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Cheers,
Stan H.
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Answer by ikleyn(52878)   (Show Source): You can put this solution on YOUR website!
.
In the equation above, a and b are constants. If . what is the value of a?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

If   =   then  (a+bi) is the number reciprocal to  :


a + bi =   =  ,


and all we need to do is to rid of the denominator in  the fraction  .

For it, multiply the fraction by  .  Since the last fraction is 1, multiplication will not change our number  .
People also say "let us multiply the numerator and the denominator of an original fraction by (3-i) ").


So, we have  

    =  = 

and since  = -1,

=  =  = 0.5 - 0.5*i.


Thus we got  a + bi = 0.5 - 0.5*i.

It implies  a = 0.5,  b = -0.5.  The problem is solved.  Your answer is: a = 0.5,  b = -0.5.

On complex numbers, you have these lessons
    - Complex numbers and arithmetic operations on them
    - Complex plane
    - Addition and subtraction of complex numbers in complex plane
    - Multiplication and division of complex numbers in complex plane
    - Raising a complex number to an integer power
    - How to take a root of a complex number
    - Solution of the quadratic equation with real coefficients on complex domain
    - How to take a square root of a complex number
    - Solution of the quadratic equation with complex coefficients on complex domain
in this site.

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