SOLUTION: The given number [((1+i)i+1)i]i+1 is equivanlent to A) 0 B) 1-i C) 1 D) 1+i

Question 1042606: The given number [((1+i)i+1)i]i+1 is equivanlent to
A) 0
B) 1-i
C) 1
D) 1+i
Found 2 solutions by jim_thompson5910, ikleyn:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Use the fact that i = sqrt(-1), so i^2 = -1

[((1+i)i+1)i]i+1
[(i+i^2+1)i]i+1
[(i+(-1)+1)i]i+1
[(i+0)i]i+1
[(i)*i]i+1
i^2*i+1
(-1)*i+1
-i+1
1-i

The final answer is choice B) 1-i
Answer by ikleyn(52894) (Show Source): You can put this solution on YOUR website!
.
Is "i" = or it is some other number? May be, real?

When sending posts like this one, it must be specially pointed.

I am not going to read behind your post.

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