SOLUTION: which of the following polynomials has a factor of x-1?. A) {{{p(x)=x^3+x^2-2x+1}}} B) {{{q(x)=2x^3-x^2+x-1}}} c) {{{r(x)=3x^3-x-2}}} D) {{{s(x)=-3x^3+3x+1}}}

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Question 1040787: which of the following polynomials has a factor of x-1?.
A)
B)
c)
D)

Found 2 solutions by jim_thompson5910, ikleyn:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
By the remainder theorem, if x-k is factor of p(x), then p(k) = 0.

In this case, x-k = x-1, so k = 1. Therefore, if we find a function p(x) such that p(k) = p(1) = 0 then we have found the answer.

Essentially we plug in x = 1 into each answer choice. Then we see which results in 0.

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Let's go through the answer choices one by one. Starting with choice A


Replace every x with 1




Since the result is NOT equal to 0, this means that x-1 is NOT a factor of p(x).

--------------------------------------------
Now onto choice B. Like before, plug in x = 1 to see if we get a result of 0.


Replace every 'x' with 1




Again we don't get 0. So choice B is not the answer either.
--------------------------------------------
Part C)


Plug in x = 1




We got a result of 0, so x-1 is a factor of r(x). We have our answer. Let's check part D just to complete the problem.
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Part D)


Plug in x = 1




The nonzero result means x-1 is not a factor of s(x)
--------------------------------------------

To summarize, the final answer is Choice C

Answer by ikleyn(52857)   (Show Source): You can put this solution on YOUR website!
.
which of the following polynomials has a factor of x-1?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Those and only those that have the number "1" as their root.

(based on the "Remainder theorem", see the lesson Divisibility of polynomial f(x) by binomial x-a in this site).

A)  = 

B)  = 

c)  =          <--- This and only this

D)  = 


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