SOLUTION: Find the value of k if the line 3x-y+1-0 is parallel to the line (k-2)x-ky+2=0
Isn't the gradient 3, then what do you do
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Question 1039201: Find the value of k if the line 3x-y+1-0 is parallel to the line (k-2)x-ky+2=0
Isn't the gradient 3, then what do you do
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
y=3x+1 if the first equation is equal to 0.
ky=(k-2)x+2
y=[(k-2)]/k +(2/k)
the two are parallel.
3 therefore equals (k-2)/k
3k=k-2, by cross-multiplication
2k=-2
k=-1
check
-3x+y+2=0
y=3x-2
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