No, that'd be too much work!



2x - 1 = 3 ------- EXPONENTS are equal, and so are the BASES 

2x = 3 + 1

2x = 4

 

Answer by ikleyn(52863)   (Show Source): You can put this solution on YOUR website!
 .

(2x-1)^2 = 9

Solve for x.



Do I expand the brackets?

~~~~~~~~~~~~~~~~~~~~~~~~~~~





The are two solutions:  x = 2 and x = -1.





(2x-1)^2 = 9 --->  2x-1 = +/-3  --->  x = 2  or/and  x = -1.


 

RELATED QUESTIONS

find the solution of x(x-9)=0
(do i need to expand the... (answered by mananth)

Hi, 
How do you expand brackets when there's three values in a bracket?
For example how  (answered by solver91311)

How do I expand (x+1)^3
I need to know the rule for expanding cubed brackets in general.
 (answered by josgarithmetic)

Question:

x²+y²=13
2x+y=1

I then tried to solve by substitution:

y=1-2x... (answered by rapaljer,AnlytcPhil)

Expand and simplify the following expression:

(x+2y-3) (2x-y+1) (x+y)

I tried... (answered by solver91311)

Expand the brackets in the following expressions.

1) (2m − 9)(5m + 4)

2) (3m... (answered by Fombitz)

Solve: [2x+5y]=[1] for y
       [ x+3y] [0] 

I hope this made sense. The brackets... (answered by Nate)

Please help me with these questions I have for my year nine homework.
1 Simplify the... (answered by rmromero)

How do i graph y-2=[x+3]  and y=[2x-1]? I don't really get the how to graph with the... (answered by Earlsdon)