SOLUTION: 2x-3y=16 where x=3y+11 Have tried 2x-3y+3y+11=16 2x+11-11=16-11 2x=5 but answer cannot be fraction what am I doing wrong here should I solve the problem 2x-3y=16 first then ans

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Question 1009655: 2x-3y=16 where x=3y+11 Have tried 2x-3y+3y+11=16 2x+11-11=16-11 2x=5 but answer cannot be fraction what am I doing wrong here should I solve the problem 2x-3y=16 first then answer would be = -3

Found 2 solutions by addingup, Edwin McCravy:
Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
2x-3y=16 where x=3y+11, so let's substitute in the equation:
2(3y+11)-3y= 16
6y+22-3y= 16 Simplify y on left and subtract 22 from both sides:
3y= -6 Divide both sides by 3
y= -2 Let's plug it in the equation and find x:
-------------------------------------
2x-3(-2)= 16
2x+6= 16
2x= 10
x= 5
-------------------------------
So there you have it:
y= -2
x= 5
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
You must learn to substitute:
       

                2x-3y=16 where x=3y+11 

Replace the x in the first equation by what x equals in the
second equation, 3y+11, placed in parentheses (3y+11):

          2(3y+11)-3y=16   

Distribute to remove the parentheses

             6y+22-3y=16  

Combine the two like terms on the left 6y and -3y, getting 3y

                3y+22=16

Add -22 to both sides

                3y+22=16
                  -22=-22
               -----------
                3y   =-6

Divide both sides by 3

                

                

Now substitute (2) for y in 
         
                x=3y+11
                x=3(-2)+11
                x=-6+11
                x=5 

 Edwin
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